Export param data without including name

Param
1

Is it possible to export parameter data from a parameterized object without including the name?

From one of

obj1.param.values()
obj1.param.serialize_parameters()
2

Currently using:

without_name = lambda d: {key:d[key] for key in d if key!='name'}
data = without_name(obj1.param.values())
3

Actually, this is kind of cool, just added a .values() method to the parameterized class.

import param as pm
class MyCoolClass(pm.Parameterized):
    p = pm.String("Hello")    

    def values(self):
        without_name = lambda d: {key:d[key] for key in d if key!='name'}
        return without_name(self.param.values())