How to find a widget that user clicked in PANEL PYTHON?

Panel
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1

Hello everyone,
I have an empty dictionary, options = {} , and I am appending various widgets like Select, TextInput etc. in the dictionary and then showing the same in the UI.
I want to find the name of the widget that the user is clicking. How do I do that ?

2

Untested but something along the lines of.

import panel as pn

pn.extension()

def callback(event):
    print(event.obj.name)

text_in = pn.widgets.TextInput()
text_in.param.watch(callback, "value")
text_in.servable()
3

Hey @ahuang11 for your reply,
but my issue is that I have hundreds of ‘TextInput’ widgets present in my application and I want to check which widget the user is editing without having to set ‘.watch’ for all of them('TextInput widgets).
Is there a way I can listen to my mouse/cursor and register the widget clicked by the user ?
Thank You

4

Perhaps you can put all the text input widgets in a list and then loop through?

5

Yes, I followed the same and it worked. Thank You. :blush:

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